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Let R1 be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2 be another relation from B to C = {1, 2, 3, 4} as defined below:
  1. An element x in A is related to an element y in B (under R1) if x + y is divisible by 3.
  2. An element x in B is related to an element y in C (under R2) if x + y is even but not divisible by 3.
 
Q. Which is the composite relation R1R2 from A to C?  
  • a)
    R1R2 = {(1, 2), (1, 4), (3, 3), (5, 4), (7, 3)}
  • b)
    R1R2 = {(1, 2), (1, 3), (3, 2), (5, 2), (7, 3)}
  • c)
    R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}
  • d)
    R1R2 = {(3, 2), (3, 4), (5, 1), (5, 3), (7, 1)}
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be...
R1 is a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} . Under R1, an element x in A is related to an element y in B if x + y is divisible by 3. 
Thus, R1 = {(1, 2), (1, 8), (3, 6), (5, 4), (7, 2), (7, 8)} 
R2 is a relation from B = {2, 4, 6, 8} to C = {1, 2, 3, 4} Under R2, an element y in B is related to an element z in C if y + z is even but not divisible by 3. 
Thus, R2 = {(2, 2), (4, 4), (6, 2), (6, 4), (8, 2)} 
Thus, R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)} 
 
Thus, option (C) is correct. 
 
Please comment below if you find anything wrong in the above post.
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Most Upvoted Answer
Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be...
Composite Relation R1R2 from A to C

R1 = {(1, 2), (1, 4), (3, 2), (3, 8), (5, 2), (5, 8), (7, 2), (7, 8)}

R2 = {(2, 1), (2, 3), (4, 1), (4, 3), (6, 1), (6, 3), (8, 1)}

To find the composite relation R1R2 from A to C, we need to find all ordered pairs (x, z) where there exists an element y such that (x, y) ∈ R1 and (y, z) ∈ R2.

R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}

Explanation:

To find R1R2 we need to check if x from A is related to y in B under R1 and if y is related to z in C under R2.

For example, (1, 2) ∈ R1R2 because (1, 2) ∈ R1 and (2, 1) ∈ R2. Similarly, (3, 2) ∈ R1R2 because (3, 2) ∈ R1 and (2, 1) ∈ R2.

However, (1, 3) is not in R1R2 because there is no element y in B such that (1, y) ∈ R1 and (y, 3) ∈ R2. Similarly, (3, 3) is not in R1R2 because there is no element y in B such that (3, y) ∈ R1 and (y, 3) ∈ R2.

Therefore, the correct answer is option C, R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}.
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Community Answer
Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be...
R1 is a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} . Under R1, an element x in A is related to an element y in B if x + y is divisible by 3. 
Thus, R1 = {(1, 2), (1, 8), (3, 6), (5, 4), (7, 2), (7, 8)} 
R2 is a relation from B = {2, 4, 6, 8} to C = {1, 2, 3, 4} Under R2, an element y in B is related to an element z in C if y + z is even but not divisible by 3. 
Thus, R2 = {(2, 2), (4, 4), (6, 2), (6, 4), (8, 2)} 
Thus, R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)} 
 
Thus, option (C) is correct. 
 
Please comment below if you find anything wrong in the above post.
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Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be another relation from B to C = {1, 2, 3, 4} as defined below: An element x in A is related to an element y in B (under R1) if x + y is divisible by 3. An element x in B is related to an element y in C (under R2) if x + y is even but not divisible by 3.Q.Which is the composite relation R1R2from A to C? a)R1R2 = {(1, 2), (1, 4), (3, 3), (5, 4), (7, 3)}b)R1R2 = {(1, 2), (1, 3), (3, 2), (5, 2), (7, 3)}c)R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}d)R1R2 = {(3, 2), (3, 4), (5, 1), (5, 3), (7, 1)}Correct answer is option 'C'. Can you explain this answer?
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Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be another relation from B to C = {1, 2, 3, 4} as defined below: An element x in A is related to an element y in B (under R1) if x + y is divisible by 3. An element x in B is related to an element y in C (under R2) if x + y is even but not divisible by 3.Q.Which is the composite relation R1R2from A to C? a)R1R2 = {(1, 2), (1, 4), (3, 3), (5, 4), (7, 3)}b)R1R2 = {(1, 2), (1, 3), (3, 2), (5, 2), (7, 3)}c)R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}d)R1R2 = {(3, 2), (3, 4), (5, 1), (5, 3), (7, 1)}Correct answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be another relation from B to C = {1, 2, 3, 4} as defined below: An element x in A is related to an element y in B (under R1) if x + y is divisible by 3. An element x in B is related to an element y in C (under R2) if x + y is even but not divisible by 3.Q.Which is the composite relation R1R2from A to C? a)R1R2 = {(1, 2), (1, 4), (3, 3), (5, 4), (7, 3)}b)R1R2 = {(1, 2), (1, 3), (3, 2), (5, 2), (7, 3)}c)R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}d)R1R2 = {(3, 2), (3, 4), (5, 1), (5, 3), (7, 1)}Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let R1be a relation from A = {1, 3, 5, 7} to B = {2, 4, 6, 8} and R2be another relation from B to C = {1, 2, 3, 4} as defined below: An element x in A is related to an element y in B (under R1) if x + y is divisible by 3. An element x in B is related to an element y in C (under R2) if x + y is even but not divisible by 3.Q.Which is the composite relation R1R2from A to C? a)R1R2 = {(1, 2), (1, 4), (3, 3), (5, 4), (7, 3)}b)R1R2 = {(1, 2), (1, 3), (3, 2), (5, 2), (7, 3)}c)R1R2 = {(1, 2), (3, 2), (3, 4), (5, 4), (7, 2)}d)R1R2 = {(3, 2), (3, 4), (5, 1), (5, 3), (7, 1)}Correct answer is option 'C'. Can you explain this answer?.
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